Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 3 (Q.No. 17)
17.
The specific weight of water in S.I. units is taken as
Discussion:
5 comments Page 1 of 1.
MORA RAMESH KUMAR said:
7 months ago
According to me, D is the correct answer.
Ajay said:
4 years ago
A and c both are correct.
a) 1000*9.81 N/m^3 ie. 9.81KN/m^3.
C) (1000*9.81)/(10^-9) N/mm^3 ie . 9.81*10^-6.
a) 1000*9.81 N/m^3 ie. 9.81KN/m^3.
C) (1000*9.81)/(10^-9) N/mm^3 ie . 9.81*10^-6.
Amit said:
4 years ago
Both option A and C are correct.
Amit said:
4 years ago
I think A and c both are right.
Rajkumar Nayak said:
10 years ago
Specific weight =density Xg.
= 1000 x 9.81 N/m^3.
= 9.81 KN/m^3.
= 1000 x 9.81 N/m^3.
= 9.81 KN/m^3.
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