Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 8 (Q.No. 35)
35.
In a footstep bearing, if the radius of the shaft is doubled, then the torque required to overcome the viscous resistance will be
Discussion:
5 comments Page 1 of 1.
Piyush Kumar said:
4 years ago
The torque required to overcome the viscous resistance of footstep bearing is (u^2*N*r^4/60t).
Here, u = viscosity of Oil, N = speed of the shaft, t= thickness of Oil film and r = radius of the shaft
So T is directly proportional to r^4.
Here, u = viscosity of Oil, N = speed of the shaft, t= thickness of Oil film and r = radius of the shaft
So T is directly proportional to r^4.
GOPI said:
8 years ago
T is directly proportional to D4. So the answer is 16.
Kajal said:
8 years ago
Torque= Π*N*r^4/60t.
SURAJIT BISWAS said:
10 years ago
k means?
Chetan jain said:
1 decade ago
As torque on footstep bearing is given by,
T = kR^4.
T = kR^4.
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