Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 4 (Q.No. 15)
15.
The power absorbed (in watts) in overcoming the viscous resistance of a footstep bearing is
Discussion:
6 comments Page 1 of 1.
Vikramsheth said:
8 years ago
Power = 2*NT/60
N = speed of shaft
T = torque
Now T = u*n^2*N^2*R^4.
.
So putting value of T in the formula of power we get answer B.
N = speed of shaft
T = torque
Now T = u*n^2*N^2*R^4.
.
So putting value of T in the formula of power we get answer B.
Nani said:
4 years ago
Here we need to divide entire formula by 60, because in question it is mentioned clearly power (in watts).
Jyoti said:
4 years ago
P = T*w.
T = f*r.
F = UAV/y.
Y = t/2,
V = pick DM/60.
W = 2πN/60.
T = f*r.
F = UAV/y.
Y = t/2,
V = pick DM/60.
W = 2πN/60.
Mach said:
8 years ago
Can anybody explain this?
Akash said:
8 years ago
Can Anybody explain this?
Deepak said:
9 years ago
Can anyone explain this?
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