Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 2 (Q.No. 29)
29.
The loss of pressure head in case of laminar flow is proportional to
Discussion:
15 comments Page 2 of 2.
Akshay said:
9 years ago
4flv2/2gd is a loss of pressure head and velocity is taken.
Whereas 32vl/d2 is a pressure drop and here average velocity is calculated.
Hence the answer given is contradictory.
Whereas 32vl/d2 is a pressure drop and here average velocity is calculated.
Hence the answer given is contradictory.
Ravi said:
1 decade ago
In q they called loss of pressure head not friction head loss. So I think answer is right.
Shiva said:
1 decade ago
For Laminar flow :
Loss of head = hF = [32*u*V(average)L]/r*g*d^2.
For turbulent flow:
HF = (flv^2)/(2*g*d).
Loss of head = hF = [32*u*V(average)L]/r*g*d^2.
For turbulent flow:
HF = (flv^2)/(2*g*d).
Kadri Aejaj said:
1 decade ago
Answer is right.
Loss of head = [32u*V(average)L]/r*g*d^2.
V(Average) = Average velocity.
Loss of head = [32u*V(average)L]/r*g*d^2.
V(Average) = Average velocity.
Hrishikesh said:
1 decade ago
I think answer is (velocity)2.
As change(pressure) = row*g*h.
h=flv2/2gd.
So change(pressure) directly proportional to v2.
As change(pressure) = row*g*h.
h=flv2/2gd.
So change(pressure) directly proportional to v2.
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