Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 1 (Q.No. 25)
25.
The loss of head due to friction in a pipe of uniform diameter in which a viscous flow is taking place, is (where RN = Reynold number)
Discussion:
22 comments Page 1 of 3.
Dwaipayan Gupta said:
4 years ago
16/Re is the Reynolds number.
Ref. R.K.Bansal, Som-Biswas-Chakraborty, F.M. White.
Ref. R.K.Bansal, Som-Biswas-Chakraborty, F.M. White.
Purbajyoti goswami said:
7 years ago
If there is friction head loss occur then option C is correct.
Aniket said:
7 years ago
If F= friction factor then F=64/Re.
but friction factor = 4* coefficient of friction,
So, if f= coe. of friction then f=16\Re,
Above is for laminar flow.
but friction factor = 4* coefficient of friction,
So, if f= coe. of friction then f=16\Re,
Above is for laminar flow.
(2)
Anand Krishnan said:
7 years ago
Fanning friction factor for tube flow:.
This friction factor is one-fourth of the Darcy friction factor, so attention must be paid to note which one of these is meant in the "friction factor" chart or equation consulted of the two, the Fanning friction factor is the more commonly used by chemical engineers and those following the British convention.
This friction factor is one-fourth of the Darcy friction factor, so attention must be paid to note which one of these is meant in the "friction factor" chart or equation consulted of the two, the Fanning friction factor is the more commonly used by chemical engineers and those following the British convention.
Paradox said:
8 years ago
It's the darcy's Coeff of friction.
For viscous-16/Re.
Turbulent-0.0791/Re.
For viscous-16/Re.
Turbulent-0.0791/Re.
ASHOK said:
8 years ago
Thanks @Bks.
Mahendra said:
8 years ago
1st the question should be coefficient of friction instead of loss of head.
W.k.t Darcy's Weinberg equation (i.e).
(4flv^2)/2gd,
Where, F=4f ; f- coefficient of friction.
(i.e)The friction factor is F = 64/Re,
Then coeff of friction 4f= 64/Re.
we get f=16/R6.
W.k.t Darcy's Weinberg equation (i.e).
(4flv^2)/2gd,
Where, F=4f ; f- coefficient of friction.
(i.e)The friction factor is F = 64/Re,
Then coeff of friction 4f= 64/Re.
we get f=16/R6.
(1)
Ramakrishna said:
9 years ago
Friction factor = 4 * friction coefficient.
Shubham said:
9 years ago
f is coefficient of friction while F is friction factor.
4f = F.
So, it can be both but first f must be specified in many books both friction factor and frictional coefficient are denoted same as 'f'.
4f = F.
So, it can be both but first f must be specified in many books both friction factor and frictional coefficient are denoted same as 'f'.
Ashwani said:
9 years ago
The Darcy friction factor f for laminar flow in a circular pipe (Reynolds number less than 2320) is given by the formula.
f = 64/Re.
f = 64/Re.
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