Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 4 (Q.No. 10)
10.
When a cylindrical vessel of radius (r) containing liquid is revolved about its vertical axis ω rad/s, then depth of parabola which the liquid assumes is
Discussion:
3 comments Page 1 of 1.
Angesh said:
8 years ago
The depth of parabola is due to velocity head of liquid i.e Vsquare/2g.and v=rw so depth=Wsquare.Rsquare/2g.
So, Answer B is correct.
So, Answer B is correct.
(1)
Nadim said:
1 decade ago
Can anyone explain?
Vishu said:
10 years ago
From pressure distribution equation of force vortex flow (cylindrical).
Between two point 1 & 2 , 1 corresponds to centre and 2 correspond near to wall of cylinder
(P2 " P1)/Rho*g =(omega^2 (r^2-0))/2.
P2 = Pa +Rho gh.
P1 = Pa.
r1 = 0.
Between two point 1 & 2 , 1 corresponds to centre and 2 correspond near to wall of cylinder
(P2 " P1)/Rho*g =(omega^2 (r^2-0))/2.
P2 = Pa +Rho gh.
P1 = Pa.
r1 = 0.
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