Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 1 (Q.No. 49)
49.
In open channels, the specific energy is the
Discussion:
2 comments Page 1 of 1.
Deepak Rathva said:
7 years ago
I think D is also correct.
Specific energy = h + (v^2/2g).
Above free surface we have to add only v^2 / 2g.
Specific energy = h + (v^2/2g).
Above free surface we have to add only v^2 / 2g.
Panka said:
8 years ago
The specific energy always remain constant for uniform flow, while total energy decrease.
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