Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 8 (Q.No. 20)
20.
The pressure of fluid due to hammer blow is
Discussion:
14 comments Page 1 of 2.
Ranjeet said:
4 years ago
For rigid pipe rise in pressure due to sudden closer of valve is,
P= density x velocity x √(bulk modulus/density).
P= density x velocity x √(bulk modulus/density).
Syed yameen said:
5 years ago
Pressure= density x velocity x celerity.
c= √k/density.
Solve for the values we get option C is correct.
c= √k/density.
Solve for the values we get option C is correct.
Manoj patel said:
5 years ago
For water hammer case pressure equal V root density/root (1/k+D/tE) so pressure is directly proportional to root density.
Babusri said:
6 years ago
C= √k/density.
Pressure directly proportional to. Density *C.
So, the answer is √density.
Pressure directly proportional to. Density *C.
So, the answer is √density.
Raghav said:
6 years ago
P = v(k.Density) ^1/2.
Romieo said:
6 years ago
How?
Krishna sarkar said:
6 years ago
The Correct answer is D.
Eva said:
6 years ago
Yes, option D is correct.
Saim said:
7 years ago
The Formula is √bulk modulus/density.
That's why the answer is D.
That's why the answer is D.
Nirmal said:
8 years ago
That depends on pipe is rigid or elastic for rigid:- option A is correct.
Elastic:- option C is correct.
Elastic:- option C is correct.
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