Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion
Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 2 (Q.No. 25)
25.
The sensible heat factor during the heating and humidification process is given by (where h1 = Enthalpy of air entering the heating coil, h2 = Enthalpy of air leaving the heating coil, and hA = Enthalpy of air at the end of humidification process)
Discussion:
6 comments Page 1 of 1.
Sunny said:
9 months ago
The Right answer is ( D).
For heat and humidification hA-h1/h2-h1.
Cooling and dehumidification hA-h2/h2-h1.
For heat and humidification hA-h1/h2-h1.
Cooling and dehumidification hA-h2/h2-h1.
UDAY said:
8 years ago
Yeah, I agree @Vishwas Patel.
Vishwas Patel said:
10 years ago
I think given answer is wrong.
Because SHF = (SHL)/(SHL + LHL).
= (h2-h1)/(h2-h1 + ha-h2).
= (h2-h1)/(ha-h1).
Because SHF = (SHL)/(SHL + LHL).
= (h2-h1)/(h2-h1 + ha-h2).
= (h2-h1)/(ha-h1).
(1)
DJ@Rocks said:
10 years ago
Why hA = Enthalpy of air at the end of humidification process).
What is the meaning of end?
What is the meaning of end?
Mohammed Riyas M said:
10 years ago
SHF = Sensible heat/(Sensible heat + Latent heat).
So answer might be (h2-h1)/(ha-h1).
So answer might be (h2-h1)/(ha-h1).
Harry said:
1 decade ago
Heat and Humidification = (ha-h1)/(h2-h1).
Cooling and Dehumidification = (ha-h2)/(h1-h2).
Cooling and Dehumidification = (ha-h2)/(h1-h2).
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