Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion
Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 7 (Q.No. 46)
46.
In actual air-conditioning applications for R-12 and R-22, and operating at a condenser temperature of 40° C and an evaporator temperature of 5° C, the heat rejection factor is about
Discussion:
13 comments Page 2 of 2.
Dixit said:
6 years ago
Here, it is 1.125.
Milan said:
6 years ago
cop= t1/t1-t2 = 313/313-278 = 8.94.
hrf = 1+1/cop= 1 + 1/8.94 = 1.11 so its 1.25.
hrf = 1+1/cop= 1 + 1/8.94 = 1.11 so its 1.25.
Girija Sankar Murmu said:
6 years ago
HRF = (heat rejected/heat absorbed) = 1+1/COP = T1/T2 = 313k/278k = 1.125.
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