Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion

Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 4 (Q.No. 33)
33.
The C.O.P. of a heat pump working on a reversed Carnot cycle is
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
7 comments Page 1 of 1.

KISHOR said:   1 decade ago
T2 is higher and T1 is lower temp considered here.

CP of heat pump = 1+ COP of ref.

Suraj said:   8 years ago
D is for refrigeration. A is the correct answer.

Jehan said:   7 years ago
If t2 is higher temp then B is correct.

Tejaa said:   7 years ago
The COP of refrigeration is {T1/(T2-T1)} so the cop of the heat pump is {T2/T2-T1)}.

Ref: R S Khurmi.

Saur said:   6 years ago
It depends on the temperature.

If T1 is greater than T2 then option A is correct.

And if T2 is greater than T1 then option D is correct.

Kajal patil said:   5 years ago
According to me, Option A gives the COP of refrigerator.

Kajal patil said:   5 years ago
COP 'for HP= (higher source temp)/(work input) --->(1)
Here,
If we consider T1- as lower sink temp.
T2- as higher source temp.

Therefore, work input = (T2-T1).
Hence COP should be from (1).
COP= T2 / (T2-T1).-->Ans D is correct.

Now, think about Option. A.
Here,
If we consider T2- as lower sink temp
T1- as higher source temp.
Work input should be (higher temp - lower temp) = (T1-T2),
Hence COP should be from (1),
COP = T1 / (T1 - T2).

But they have given it as a WD= (T2 - T1) which is not possible.
Hence option (A) is incorrect.

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