Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion
Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 4 (Q.No. 33)
                   
                                       
                                33.
The C.O.P. of a heat pump working on a reversed Carnot cycle is
 
                                    Discussion:
7 comments Page 1 of 1.
                
                        KISHOR said: 
                         
                        1 decade ago
                
                T2 is higher and T1 is lower temp considered here.
CP of heat pump = 1+ COP of ref.
                CP of heat pump = 1+ COP of ref.
                        Suraj said: 
                         
                        8 years ago
                
                D is for refrigeration. A is the correct answer.
                
                        Jehan said: 
                         
                        8 years ago
                
                If t2 is higher temp then B is correct.
                
                        Tejaa said: 
                         
                        7 years ago
                
                The COP of refrigeration is {T1/(T2-T1)} so the cop of the heat pump is {T2/T2-T1)}.
Ref: R S Khurmi.
                Ref: R S Khurmi.
                        Saur said: 
                         
                        6 years ago
                
                It depends on the temperature.
If T1 is greater than T2 then option A is correct.
And if T2 is greater than T1 then option D is correct.
                If T1 is greater than T2 then option A is correct.
And if T2 is greater than T1 then option D is correct.
                        Kajal patil said: 
                         
                        5 years ago
                
                According to me, Option A gives the COP of refrigerator.
                
                        Kajal patil said: 
                         
                        5 years ago
                
                COP 'for HP= (higher source temp)/(work input) --->(1)
Here,
If we consider T1- as lower sink temp.
T2- as higher source temp.
Therefore, work input = (T2-T1).
Hence COP should be from (1).
COP= T2 / (T2-T1).-->Ans D is correct.
Now, think about Option. A.
Here,
If we consider T2- as lower sink temp
T1- as higher source temp.
Work input should be (higher temp - lower temp) = (T1-T2),
Hence COP should be from (1),
COP = T1 / (T1 - T2).
But they have given it as a WD= (T2 - T1) which is not possible.
Hence option (A) is incorrect.
                Here,
If we consider T1- as lower sink temp.
T2- as higher source temp.
Therefore, work input = (T2-T1).
Hence COP should be from (1).
COP= T2 / (T2-T1).-->Ans D is correct.
Now, think about Option. A.
Here,
If we consider T2- as lower sink temp
T1- as higher source temp.
Work input should be (higher temp - lower temp) = (T1-T2),
Hence COP should be from (1),
COP = T1 / (T1 - T2).
But they have given it as a WD= (T2 - T1) which is not possible.
Hence option (A) is incorrect.
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