Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion
Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 8 (Q.No. 23)
23.
The C.O.P. of a refrigerator working on a reversed Carnot cycle is (where T1 = Lowest absolute temperature, and T2 = Highest absolute temperature)
Discussion:
6 comments Page 1 of 1.
Aswanth said:
3 years ago
This answer is correct, reverse Carnot cycle working on refrigerator =T1/T2-T1.
(Carnot cycle working on refrigerator = T2/T1-T2).
(Carnot cycle working on refrigerator = T2/T1-T2).
Vikram said:
6 years ago
COP = low temp/ (high temp- low temp).
So, the Answer is COP=T1/(T2-T1).
So, the Answer is COP=T1/(T2-T1).
KUSALI said:
6 years ago
Answer is the correct as they have changed conventional notations.
Santosh said:
6 years ago
Reverse Carnot cycle working on heat pump = T2/T2-T1.
Mohii said:
7 years ago
T2/(T1-T2) should be the right answer.
Tejaa said:
7 years ago
The formula is given as T2/(T1-T2).
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