# Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion

5.

A heat pump working on a reversed Carnot cycle has a C.O.P. of 5. It works as a refrigerator taking 1 kW of work input. The refrigerating effect will be

 [A]. 1 kW [B]. 2 kW [C]. 3 kW [D]. 4 kW

Explanation:

No answer description available for this question.

 Sachin said: (Dec 1, 2013) cop>p = 1+cop>r. 5 = 1+----. cop>r = 4. cop>r = RE/WC. 4 = RE/1. RE = 4.

 Mohit Kumar(Pmv) said: (Mar 21, 2014) (C.O.P) of heat pump-(C.O.P) of refrigerator = 1. 5 = 1+(COP)Refri. So, (cop)Refri. = 4.

 Saidulu.K said: (Sep 8, 2014) cop(heat pump) = 1+cop(R effect). R = Refrigeration. 5 = 1+cop(R effect). cop(R effect) = 5-1. cop(R effect) = 4.

 Jnk said: (Aug 11, 2016) COP of hp = 1+ COP of refrig.

 Ravi Gujjar said: (Oct 22, 2016) In a refrigerator, COP = Referigeration Effect /work input_________(i) (C.O.P) of heat pump - (C.O.P) of refrigerator = 1. 5 = 1 + (COP)Refrigeration. SO, (COP) Refrigeration = 4. From equation (i) we get; Refrigeration effect = 4 *1 KW = 4 KW.

 Arunkumar said: (Jun 23, 2017) COP (H. P) = COP (R. E) +1. ie, From the question we know that, 5= COP (R. E) +1. hence COP (R. E)= 5-1 = 4.

 Vaddu Ramkumar said: (Jul 27, 2020) Cop of heat pump = 1 + cop of (refrigerating effect) 5 = 1 + cop ( refrigerating effect). Cop of (refrigeration effect) = 5 - 1 = 4.

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