Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion

5. 

A heat pump working on a reversed Carnot cycle has a C.O.P. of 5. It works as a refrigerator taking 1 kW of work input. The refrigerating effect will be

[A]. 1 kW
[B]. 2 kW
[C]. 3 kW
[D]. 4 kW

Answer: Option D

Explanation:

No answer description available for this question.

Sachin said: (Dec 1, 2013)  
cop>p = 1+cop>r.
5 = 1+----.
cop>r = 4.

cop>r = RE/WC.
4 = RE/1.

RE = 4.

Mohit Kumar(Pmv) said: (Mar 21, 2014)  
(C.O.P) of heat pump-(C.O.P) of refrigerator = 1.

5 = 1+(COP)Refri.

So, (cop)Refri. = 4.

Saidulu.K said: (Sep 8, 2014)  
cop(heat pump) = 1+cop(R effect). R = Refrigeration.

5 = 1+cop(R effect).

cop(R effect) = 5-1.

cop(R effect) = 4.

Jnk said: (Aug 11, 2016)  
COP of hp = 1+ COP of refrig.

Ravi Gujjar said: (Oct 22, 2016)  
In a refrigerator, COP = Referigeration Effect /work input_________(i)

(C.O.P) of heat pump - (C.O.P) of refrigerator = 1.
5 = 1 + (COP)Refrigeration.
SO, (COP) Refrigeration = 4.

From equation (i) we get;
Refrigeration effect = 4 *1 KW = 4 KW.

Arunkumar said: (Jun 23, 2017)  
COP (H. P) = COP (R. E) +1.
ie, From the question we know that,

5= COP (R. E) +1.
hence COP (R. E)= 5-1 = 4.

Vaddu Ramkumar said: (Jul 27, 2020)  
Cop of heat pump = 1 + cop of (refrigerating effect)
5 = 1 + cop ( refrigerating effect).
Cop of (refrigeration effect) = 5 - 1 = 4.

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