Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion
Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 2 (Q.No. 5)
5.
A heat pump working on a reversed Carnot cycle has a C.O.P. of 5. It works as a refrigerator taking 1 kW of work input. The refrigerating effect will be
Discussion:
7 comments Page 1 of 1.
Vaddu ramkumar said:
5 years ago
Cop of heat pump = 1 + cop of (refrigerating effect)
5 = 1 + cop ( refrigerating effect).
Cop of (refrigeration effect) = 5 - 1 = 4.
5 = 1 + cop ( refrigerating effect).
Cop of (refrigeration effect) = 5 - 1 = 4.
(2)
Arunkumar said:
8 years ago
COP (H. P) = COP (R. E) +1.
ie, From the question we know that,
5= COP (R. E) +1.
hence COP (R. E)= 5-1 = 4.
ie, From the question we know that,
5= COP (R. E) +1.
hence COP (R. E)= 5-1 = 4.
(1)
Ravi gujjar said:
9 years ago
In a refrigerator, COP = Referigeration Effect /work input_________(i)
(C.O.P) of heat pump - (C.O.P) of refrigerator = 1.
5 = 1 + (COP)Refrigeration.
SO, (COP) Refrigeration = 4.
From equation (i) we get;
Refrigeration effect = 4 *1 KW = 4 KW.
(C.O.P) of heat pump - (C.O.P) of refrigerator = 1.
5 = 1 + (COP)Refrigeration.
SO, (COP) Refrigeration = 4.
From equation (i) we get;
Refrigeration effect = 4 *1 KW = 4 KW.
Jnk said:
9 years ago
COP of hp = 1+ COP of refrig.
Saidulu.k said:
1 decade ago
cop(heat pump) = 1+cop(R effect). R = Refrigeration.
5 = 1+cop(R effect).
cop(R effect) = 5-1.
cop(R effect) = 4.
5 = 1+cop(R effect).
cop(R effect) = 5-1.
cop(R effect) = 4.
Mohit kumar(pmv) said:
1 decade ago
(C.O.P) of heat pump-(C.O.P) of refrigerator = 1.
5 = 1+(COP)Refri.
So, (cop)Refri. = 4.
5 = 1+(COP)Refri.
So, (cop)Refri. = 4.
Sachin said:
1 decade ago
cop>p = 1+cop>r.
5 = 1+----.
cop>r = 4.
cop>r = RE/WC.
4 = RE/1.
RE = 4.
5 = 1+----.
cop>r = 4.
cop>r = RE/WC.
4 = RE/1.
RE = 4.
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