Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion
Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 3 (Q.No. 16)
16.
The C.O.P. of a Carnot refrigerator in winter will be __________ as compared to C.O.P. in summer.
Discussion:
7 comments Page 1 of 1.
Vikash said:
4 years ago
Cop = T low/ (Thigh-T low).
Therefore in winter, the denominator is low. And the cop is high.
Therefore in winter, the denominator is low. And the cop is high.
(1)
Nikk said:
6 years ago
Cop=desired effect/work input..
Hence in winter, both desired effect and work input will decrease.
Therefore cop increases(ratio decreases when both quantity decreases-maths) and for summer vice versa.
Hence in winter, both desired effect and work input will decrease.
Therefore cop increases(ratio decreases when both quantity decreases-maths) and for summer vice versa.
Souravchoudhury said:
7 years ago
From the expression of cop=T(low)/(Th-Tl) as the temperature of surrounding is more in summer compared to winter, so The diff between two temp is comparatively high as compared to winter. That's why ( cop) winter is greater than cop summer.
Gaurav said:
10 years ago
Because in winter it acts as heat pump.
COP of heat pump = 1+COP of refrigerator.
COP of heat pump = 1+COP of refrigerator.
Ram said:
1 decade ago
To increase cop condenser temp should be decreased and increase evaporator temp completely opposite of Rankine cycle.
Ravi said:
1 decade ago
C.O.P = T Evaporator/(T cond - T evap).
The difference between condenser temp and evaporator temp is less.
The difference between condenser temp and evaporator temp is less.
(1)
Rajesh said:
1 decade ago
What is the reason?
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