Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion
Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 5 (Q.No. 10)
10.
An infinite parallel planes with emissivities e1 and e2, the interchange factor for radiation from surface 1 to surface 2 is given by
e1 + e2
e1e2
Discussion:
2 comments Page 1 of 1.
Rajat said:
7 years ago
How? Explain me.
Joy said:
6 years ago
The interchange factor is 1/R, where R=Thermal Resistance.
So, R= (1/e1)+(1/e2)-1.
Solve and get R.
1/R is the 1st Option. Hence, the correct answer is given.
So, R= (1/e1)+(1/e2)-1.
Solve and get R.
1/R is the 1st Option. Hence, the correct answer is given.
(1)
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