Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 5 (Q.No. 37)
37.
Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its vertex and parallel to the base, is __________ than that passing through its C.G. and parallel to the base.
Discussion:
11 comments Page 2 of 2.
Bina mistry said:
1 decade ago
MI of triangular section about an axis through its CG and parallel to base = bh^3/36.
The MI of section about an axis through its vertex and parallel to the base = Ig+ad^2.
= bh^3/36 + (bh/2)(2h/3)^2.
= 9bh^3/36.
= bh^3/4.
The MI of section about an axis through its vertex and parallel to the base = Ig+ad^2.
= bh^3/36 + (bh/2)(2h/3)^2.
= 9bh^3/36.
= bh^3/4.
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