Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 5 (Q.No. 37)
37.
Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its vertex and parallel to the base, is __________ than that passing through its C.G. and parallel to the base.
Discussion:
11 comments Page 1 of 2.
Sohan said:
7 years ago
You are correct @Bina Mistry.
MI about vertex= bh^3/4.
MI about centroid=bh^3/36.
Mi about base=bh^3/12.
MI about vertex= bh^3/4.
MI about centroid=bh^3/36.
Mi about base=bh^3/12.
(1)
Lakhan Bhavnani said:
7 years ago
Thanks @Sohan.
(1)
Bina mistry said:
1 decade ago
MI of triangular section about an axis through its CG and parallel to base = bh^3/36.
The MI of section about an axis through its vertex and parallel to the base = Ig+ad^2.
= bh^3/36 + (bh/2)(2h/3)^2.
= 9bh^3/36.
= bh^3/4.
The MI of section about an axis through its vertex and parallel to the base = Ig+ad^2.
= bh^3/36 + (bh/2)(2h/3)^2.
= 9bh^3/36.
= bh^3/4.
Harsha Kalluri said:
9 years ago
When I refer this to some other websites its answer is 3 times. Which one is correct?
And, I want to know what is the formula for the MI of the section about an axis through vertex and parallel to the base.
Thank you.
And, I want to know what is the formula for the MI of the section about an axis through vertex and parallel to the base.
Thank you.
BENNY said:
9 years ago
Moment of Inertia of a Triangular area.
(a) Moment of Inertia of a Triangular area of an axis XX parallel to the base and passes through C. G.
I = BH^3/36.
Moment of inertia of a triangle about;
Axis passes through base I = BH^3/12.
(a) Moment of Inertia of a Triangular area of an axis XX parallel to the base and passes through C. G.
I = BH^3/36.
Moment of inertia of a triangle about;
Axis passes through base I = BH^3/12.
Rajesh Khutdar said:
9 years ago
It's (bh^3) / 4.
Daka said:
9 years ago
@Harsha Kalluri.
When I about an axis passing through its vertex and parallel to the base then 9 times.
And I about an axis passing through its base then 3 times.
When I about an axis passing through its vertex and parallel to the base then 9 times.
And I about an axis passing through its base then 3 times.
Hari said:
8 years ago
Well said @Daka.
Abhishek singh said:
6 years ago
Ip = IG+Ak^2
= bh^3/36+(bh/2) x (2h/3)^3
= 9bh^3/36
= bh^3/4.
Then Iv:IG
Bh^3/4:bh^3/36
1:9
= bh^3/36+(bh/2) x (2h/3)^3
= 9bh^3/36
= bh^3/4.
Then Iv:IG
Bh^3/4:bh^3/36
1:9
Abhishek said:
5 years ago
9 times is correct.
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