Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 35)
35.
Moment of inertia of a triangular section of base (b) and height (h) about an axis through its base, is
Discussion:
2 comments Page 1 of 1.
Sutanu Dutta said:
2 years ago
I think option D is correct.
Manoj said:
1 decade ago
Ib = In+AY2.
= bh3/36+(1/2)*b*h*(h/3)sqr.
= bh3/36+(1/2)*b*h*(h/3)sqr.
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