Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 41)
41.
The centre of gravity of a trapezium with parallel sides a and b lies at a distance of y from the base b, as shown in the below figure. The value of y is
Discussion:
9 comments Page 1 of 1.
Pramod said:
9 years ago
@Gaurav.
I agree with your solution and thanks for your explanation.
I agree with your solution and thanks for your explanation.
Gaurav said:
1 decade ago
Put a = b then its rectangle and centre of gravity lies at h/2.
Madan lal said:
6 years ago
Option C is correct because it is Trapezium.
Puneet said:
9 years ago
I think B is the correct answer.
Sohan said:
7 years ago
Option C is correct. I agree.
Vera said:
7 years ago
I think the answer is B.
Manohar said:
9 years ago
Thank you @Gaurav.
Dattatraya said:
8 years ago
Thank you @Gaurav.
Abhishek Arora said:
6 years ago
Thank you @Gaurav.
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