Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 6 (Q.No. 7)
7.
The force induced in the string AB due to the load W, as shown in the below figure is
Discussion:
8 comments Page 1 of 1.
Saifullah said:
6 years ago
Sin(theeta) = W/AB ; AB = W/sin(theeta) = WCosec(theeta).
Arun said:
6 years ago
W/sin is the correct one.
Ellapu Kumar said:
7 years ago
Here AB means hypotenuse and W is in opposite direction. So, hyp/opposite is cosec.
Yashwant narayan said:
8 years ago
W=ABsinθ
AB=w/sinθ
AB=Wcosecθ.
AB=w/sinθ
AB=Wcosecθ.
Crd said:
8 years ago
No use of Lami' s theorem in supposing BC has Passed force then two-part of it psin@ and pcosθ from figure W=psinθ so p=W/ sinθ, p= wcosecθ.
Rajesh Khutdar said:
9 years ago
Appreciate your answer, Thanks, @Anurag.
Anurag said:
10 years ago
By Lami's theorem.
Gajendra said:
1 decade ago
W/Sin@ = AB/Sin90.
AB = W*Cosec@.
AB = W*Cosec@.
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