Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 4 (Q.No. 1)
1.
Three forces acting on a rigid body are represented in magnitude, direction and line of action by the three sides of a triangle taken in order. The forces are equivalent to a couple whose moment is equal to
Discussion:
6 comments Page 1 of 1.
Rashid Khan Kakar said:
4 years ago
A couple will be formed when force opposite and τ in nature.
Hiralal kumar said:
5 years ago
In triangle,
M I = height * Base
Area of a triangle.
A=1/2*height*base.
2A = hight*Base.
So,
M I = 2A.
M I = height * Base
Area of a triangle.
A=1/2*height*base.
2A = hight*Base.
So,
M I = 2A.
(2)
P.devisri said:
7 years ago
I did not understand this, please explain the answer.
Rajat said:
7 years ago
Find the moment by taking an equilateral (for simplicity) triangle about its centroid. By taking forces equal represented by sides of the triangle.
We get total moment = double the area of a triangle.
We get total moment = double the area of a triangle.
Karthik said:
8 years ago
Anyone explain it?
Manoj said:
8 years ago
I can't understand it. Can anyone clarify it?
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