Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 49)
49.
two like parallel forces are acting at a distance of 24 mm apart and their resultant is 20 N. It the line of action of the resultant is 6 mm from any given force, the two forces are
Discussion:
24 comments Page 2 of 3.
Praveen said:
6 years ago
This is to be solved by Varignon's Theorem.
Consider a point A.
Moment of F1 about A + Moment of F2 about A = Moment of R about A.
Consider a point A.
Moment of F1 about A + Moment of F2 about A = Moment of R about A.
Kaku said:
7 years ago
F1 + F2 = 20N.
Taking moment about B.
R*0= -f1(6)+ f2(24-6),
0 = -(20-f2)(6) + 18f2,
F2 =5.
After putting we will get the answer.
Taking moment about B.
R*0= -f1(6)+ f2(24-6),
0 = -(20-f2)(6) + 18f2,
F2 =5.
After putting we will get the answer.
(3)
Rahul kumar said:
1 decade ago
Rahul kumar.
F1+F2=20-------> (1).
14F1-6F2=20-----> (2).
Solving equation (1)& (2).
F1 = 5N.
F2 = 15N.
F1+F2=20-------> (1).
14F1-6F2=20-----> (2).
Solving equation (1)& (2).
F1 = 5N.
F2 = 15N.
DARSHAN said:
1 decade ago
F1+F2=20......(1).
NOW,
MOMENT about Resultant
18F1-6F2=0.....(2).
By solving above eq.
We get F1=5 & F2=15.
NOW,
MOMENT about Resultant
18F1-6F2=0.....(2).
By solving above eq.
We get F1=5 & F2=15.
M. Flowers said:
1 decade ago
I'm not understanding what method you applied to get these answers. What formula was used?
Nithyananda said:
10 years ago
They are given F1=24, but I don't know why the two person taken as F1=14?
Rajesh Kadam said:
5 years ago
F1 + F2 = 20
F1*24 = R * 18
SOLVING Eq we get;
F1 = 15.
F2 = 5.
F1*24 = R * 18
SOLVING Eq we get;
F1 = 15.
F2 = 5.
(5)
Pandees waran said:
9 years ago
F1 + F2 = 20.
15 + 5 = 20 simple method.
15 + 5 = 20 simple method.
Fathima said:
10 years ago
Can you give us a schematic sketch?
Rahul s said:
8 years ago
Thank you very much @Pandees Waran.
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