Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 49)
49.
two like parallel forces are acting at a distance of 24 mm apart and their resultant is 20 N. It the line of action of the resultant is 6 mm from any given force, the two forces are
Discussion:
24 comments Page 2 of 3.
Sanjeev said:
7 years ago
Thanks @Roj.
Nikss said:
8 years ago
@ALL.
Two forces acting parallel in the same direction. So the resultant will be a single force in the same direction. So from where this clockwise and anticlockwise concept came?
All forces will be in same direction.
Two forces acting parallel in the same direction. So the resultant will be a single force in the same direction. So from where this clockwise and anticlockwise concept came?
All forces will be in same direction.
KRISH REDDY said:
8 years ago
Simple method friends.
All forces equal to the resultant is 20.
So see the option s where the 2 forces are 20 so that will be the answer. 5+15=20.
All forces equal to the resultant is 20.
So see the option s where the 2 forces are 20 so that will be the answer. 5+15=20.
M. Flowers said:
1 decade ago
I'm not understanding what method you applied to get these answers. What formula was used?
Lova said:
9 years ago
Thank you very much friends.
POPPY said:
9 years ago
Resultant R = F1 + F2 = 20N (i) F1----6mm-----R------18mm------------F2 equating clockwise moment to anticlockwise moment then, 18F2 = 6F1 THEN, F1 = 3F2, From equating in (i) we get F1=15 &F2 = 5.
Pandees waran said:
9 years ago
F1 + F2 = 20.
15 + 5 = 20 simple method.
15 + 5 = 20 simple method.
Nithyananda said:
10 years ago
They are given F1=24, but I don't know why the two person taken as F1=14?
Fathima said:
10 years ago
Can you give us a schematic sketch?
Rishi said:
1 decade ago
Where did 18f1 and 6f2 came from? I think you can simply add the forces as they are like and parallel. F1+F2=20 and option 1 satisfies it.
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