Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 7 (Q.No. 1)
1.
When a body of mass moment of inertia I (about a given axis) is rotated about that axis with an angular velocity to, then the kinetic energy of rotation is
Discussion:
9 comments Page 1 of 1.
PRITAM KUMAR said:
4 years ago
So KE = 1/2mv2.
Aman Baruah said:
5 years ago
What Mass does in linear motion same effect is given by moment of inertia in rotational motion.
So, K. E = 1/2IW2.
So, K. E = 1/2IW2.
(1)
Biplab sarkar said:
6 years ago
How it comes? explain.
Salman sadiq said:
6 years ago
How it comes 0.5iω^2? Please explain the answer in detail.
Sudarshan said:
7 years ago
Leanier velocity = (1/2) * mv"2.
Angular velocity = (1/2) * iw"2.
Angular velocity = (1/2) * iw"2.
Bragadheeshwaran said:
8 years ago
How it comes?
Explain in detail.
Explain in detail.
Suraj kumar patra said:
9 years ago
How 0. 5iω2? Explain.
Govind said:
10 years ago
But how?
Ramu said:
1 decade ago
K.E = 1/2 mv^2.
If you consider angular velocity,
K.E becomes = 0.5iω2.
If you consider angular velocity,
K.E becomes = 0.5iω2.
(1)
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