Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 4 (Q.No. 28)
28.
A body of mass m moving with a constant velocity v strikes another body of same mass m moving with same velocity but in opposite direction. The common velocity of both the bodies after collision is
Discussion:
21 comments Page 2 of 3.
Darshan said:
7 years ago
If body will move with double velocity after impact than after sometime it's velocity will be infinite.
Shankar shinde said:
1 decade ago
How it is possible sir? After collision the velocity of body will decrease instead of increase.
Prem said:
9 years ago
@Mike!
Mathematically it's V = u but practically it is zero in my perception.
Mathematically it's V = u but practically it is zero in my perception.
Manish said:
9 years ago
m1u1 + m2u2 = m1v1 + m2v2.
u1 = v
u2 = -v
0 = m (v1+v2)
m().
u1 = v
u2 = -v
0 = m (v1+v2)
m().
Sonu pandey said:
8 years ago
Here opposite direction. So,
v-(-v) = 2v.
v-(-v) = 2v.
Omid said:
6 years ago
They are asking combined velocity. So 2V.
Sandeep said:
10 years ago
Velocity after collision is zero.
BIBIN EMMANUVEL said:
8 years ago
Velocity after collision is 0.
Vinay BEL said:
5 years ago
Velocity after collision is 0.
Pradeep gk said:
8 years ago
You are correct @Tanveer.
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