Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 4 (Q.No. 28)
28.
A body of mass m moving with a constant velocity v strikes another body of same mass m moving with same velocity but in opposite direction. The common velocity of both the bodies after collision is
Discussion:
21 comments Page 1 of 3.
Shankar shinde said:
1 decade ago
How it is possible sir? After collision the velocity of body will decrease instead of increase.
Sandeep said:
10 years ago
Velocity after collision is zero.
GVR Murty said:
10 years ago
Final velocity is zero equation : m1u1+m2u2 = (m1+m2)v1;
v1 = Common velocity, mv-mv = 2mv1 --> v1 = 0.
v1 = Common velocity, mv-mv = 2mv1 --> v1 = 0.
Sohel said:
10 years ago
How its possible?
Mike said:
9 years ago
The answer is A. The reason is this:
Data given:
Initial velocity of first body = u.
Mass of first body = m.
Mass of second body = m.
Initial velocity of second body = u.
Final velocity of combined bodies = v .
Mass of combined bodies = 2m.
Therefore,
mu + mu = (m + m)v.
v = 2mu/2m = u.
Data given:
Initial velocity of first body = u.
Mass of first body = m.
Mass of second body = m.
Initial velocity of second body = u.
Final velocity of combined bodies = v .
Mass of combined bodies = 2m.
Therefore,
mu + mu = (m + m)v.
v = 2mu/2m = u.
Prem said:
9 years ago
@Mike!
Mathematically it's V = u but practically it is zero in my perception.
Mathematically it's V = u but practically it is zero in my perception.
Manish said:
9 years ago
m1u1 + m2u2 = m1v1 + m2v2.
u1 = v
u2 = -v
0 = m (v1+v2)
m().
u1 = v
u2 = -v
0 = m (v1+v2)
m().
Srinivasulu.v said:
9 years ago
It is a perfectly elastic collision, then we have a coefficient of restitution (e) is =1.
V2 - V1 = U1 - U2
but v1= u1 (say U)
Common velocities of both the bodies is v2 + u2 = = 2U
Option B is correct.
V2 - V1 = U1 - U2
but v1= u1 (say U)
Common velocities of both the bodies is v2 + u2 = = 2U
Option B is correct.
Krunal said:
8 years ago
When the bodies are elastic, then they will move with the same velocity after the collision, but in the case when the bodies are not elastic, their velocities may be zero. That's why it's hard to believe that after the collision, the bodies will have twice of the initial velocities.
Tanveer Ahmed said:
8 years ago
Here he is talking about common velocities of both which is 2v. If we talk about for a particular body then velocity will be V.
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