Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 4 (Q.No. 41)
41.
The ideal angle of banking provided on the curves on roads depends upon
Discussion:
5 comments Page 1 of 1.
Dinesh nagar said:
6 years ago
Tan θ = v^2/rg.
RAHUL said:
7 years ago
It is right, friction force of tires balances centrifugal force that is MV2/R=f=UMG.
HERE U= COEFFICIENT OF FRICTION.
M=MASS.
G =GRAVITATIONAL FORCE.
V=VELOCITY.
R=RADIUS OF TURNING.
HERE U= COEFFICIENT OF FRICTION.
M=MASS.
G =GRAVITATIONAL FORCE.
V=VELOCITY.
R=RADIUS OF TURNING.
Danish said:
9 years ago
Its answer is right because v = Gv2/gr.
Satish said:
1 decade ago
A banked turn (aka. Banking turn) is a turn or change of direction in which the vehicle banks or inclines, usually towards the inside of the turn. For a road or railroad this is usually due to the roadbed having a transverse down-slope towards the inside of the curve. The bank angle is the angle at which the vehicle is inclined about its longitudinal axis with respect to the horizontal.
Swapnil kalkote said:
1 decade ago
What is banking here?
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