Mechanical Engineering - Engineering Mechanics - Discussion

Rang or projectile always depends on projection angle.

The max range got in 45°.

During upword prjectile accleration due to gravity act negetively and during its act (+). So valocity during downward direction is more.

I think it's equal because of 'same velocity'.

Range means the horizontal distance covered by projectile.

How it is possible?

How can we classify upward projectile and downward projectile?

I think answer is option B because of for example a stone you through in upward direction while coming return it will be more speed as you all know this simple technique thank you all.

In inclined projectile

R=(u^2)/g(1(+/-)sin deta ) for up +, down -.

So,
For 45 deg ,1/(1+sin45) is 1.4.
And same, 1/(1-sin45) is 3.3.
Therefore
Down > up.

Range of projectile in a downward inclined is given by
R= (2u^2sin(a+b)cosa)/gcos^2b
Range of projectile in an upward inclined is given by
R= (2u^2sin(a-b)cosa)/gcos^2b
Where 'a' is alpha, angle made by projection with horizontal and 'b' is beta, angle made by range with horizontal.
Since the value of sin* increase from 0° to 90° and (a+b) is greater than (a-b)
The range of projectile in a downward inclined is greater than Range of the projectile in an upward inclined.

How come a range of projectile on the downward inclined plane will be more? Should it be less na?

Because speed will be more, as gravity is acting, so that distance will be covered in less time. Please, someone, clarify.