Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 3 (Q.No. 30)
30.
The maximum height of a projectile on a horizontal plane, is
Discussion:
2 comments Page 1 of 1.
Ch Asad Rasool said:
6 years ago
At max height t = t/2.
Put t = u*sin(θ)/g in 2nd equation of motion.
Put t = u*sin(θ)/g in 2nd equation of motion.
Amitesh kumar said:
7 years ago
Explain the solution of the question.
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