Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 37)
37.
The path of the projectile is a parabola.
Discussion:
3 comments Page 1 of 1.
Sakthivel said:
8 years ago
The fn of graph for a projectile is y=x^2, which is parbola?
Derrick said:
8 years ago
The path taken by a projectile is trajectory.
Manikanta ghosh said:
1 decade ago
cos@=? R^2 = P^2 +Q^2+2PQ COS@.
cos 0 = 1
cos(180) = 0
cos 0 = 1
cos(180) = 0
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