Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 6 (Q.No. 17)
17.
Two blocks A and B of masses 150 kg and 50 kg respectively are connected by means of a string as shown in the below figure. The tension in all the three strings __________ be same.
Discussion:
13 comments Page 1 of 2.
Namit said:
9 years ago
Tension in a string is always constant throughout its length. Its magnitude does not change with length.
Hugo Ariza said:
7 years ago
If Tb=50Kg and Ta=75Kg, how come that all T's are the same?
Kiran said:
7 years ago
Could you please explain in detail?
Vivek said:
7 years ago
If Tb=50Kg and Ta=75Kg, how come that all T's are the same?
How can it same? It is different tension.
How can it same? It is different tension.
(1)
Shibu s said:
7 years ago
Please explain the answer.
Justin James said:
7 years ago
By using pulley the weight reduce to half and the same on B equalizes the weight.
Prasanth b said:
7 years ago
If Tb=50Kg and Ta=75Kg, how come that all T's are the same?
Sajin s said:
7 years ago
Here, Tension[T] Is equal.
Sukhdeep Singh said:
7 years ago
The system is not in equilibrium at this point of time. We will not apply an extra 25 kg of effort at 50KG block end. To make the system in equibrium. Both Ta and Tb will be 75 Kg then. This type of system is 2nd pulley system, where the mechanical advantage will be 2 and the effort will reduce to half to become 75 Kg.
SUBHENDU MUKHERJEE said:
6 years ago
Use the formula, 2M1M2/M1+M2= 2 * 150 * 50/150 + 50 = 100 * 150/200 = 75.
So, the tension in 1st string from the right side is 75. Which is the same in the other two as 150/2 =75.
So 75 n tension in each string.
So, the tension in 1st string from the right side is 75. Which is the same in the other two as 150/2 =75.
So 75 n tension in each string.
(1)
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