Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 3 (Q.No. 1)
1.
If the masses of both the bodies, as shown in the below figure, are doubled, then the acceleration in the string will be
Discussion:
11 comments Page 1 of 2.
Mala sinha said:
5 years ago
@Aldrin.
According to the formula when you double up the masses, tension will be doubled but acceleration will be same.
a=(m1-m2)g/(m1+m2).
When we double up the masses.
Then a will be (2m1-2m2).g/(2m1+2m2).
When we will take common 2 then.
2(m1-m2).g/2(m1+m2).
Cancel 2 with 2.
Then the answer will be same.
I think this is the right answer.
According to the formula when you double up the masses, tension will be doubled but acceleration will be same.
a=(m1-m2)g/(m1+m2).
When we double up the masses.
Then a will be (2m1-2m2).g/(2m1+2m2).
When we will take common 2 then.
2(m1-m2).g/2(m1+m2).
Cancel 2 with 2.
Then the answer will be same.
I think this is the right answer.
(3)
Aldrin said:
8 years ago
Well, according to the formula when you double up the masses, the answer (ie acceleration) is also doubled. Please, could someone help me?
(1)
Ashish Baranwal said:
8 years ago
Tension is same so acceleration is also same.
(1)
Naveen said:
8 years ago
Acceleration = ((m2-m1/m2+m1)*g);m2>m1.
(1)
Mahantesh said:
9 years ago
What is mean superposition?
(1)
PRATIK said:
10 years ago
Principle of superposition.
Kamalesh said:
1 decade ago
Let us consider the weights of the two loads be 70N and 80N respectively and the two weights are balanced, if a load of 2N is added on both sides 72N and 82N will be the load. So now also it will be balanced.
Mukesh said:
1 decade ago
Both end have same tension so acceleration will be same.
Human said:
1 decade ago
Consider this, Two elephants of mass 7 ton and 8 ton are tied at the two ends of this rope. So the tension will be same and the rope will not torn ?
SatyaSwaroop said:
1 decade ago
@Rahul Baranwal: Not really (here) !In fact, the acceleration comes out to be g* (m1-m2) / (m1+m2).
The length of the string (assuming it to be inelastic) remains constant. Hence the distance between the blocks along the string remains constant. Hence the acceleration of the two blocks is constrained to be same.
Since the acceleration is g* (m1-m2) / (m1+m2) , doubling the mass doesn't affect the acceleration.
The length of the string (assuming it to be inelastic) remains constant. Hence the distance between the blocks along the string remains constant. Hence the acceleration of the two blocks is constrained to be same.
Since the acceleration is g* (m1-m2) / (m1+m2) , doubling the mass doesn't affect the acceleration.
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