Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 4 (Q.No. 2)
2.
If tension in the cable supporting a lift moving downwards is half the tension when it is moving upwards, the acceleration of the lift is
Discussion:
38 comments Page 3 of 4.
A.jay said:
8 years ago
Answer is g/3. The question doesn't asks about direction of lift so there is no point of negative g/3.
Rk reddy said:
8 years ago
g/3 is the answer.
Dheeraj kumar said:
8 years ago
g/3 if the acceleration is constant otherwise, option D.
Badan singh said:
8 years ago
Yes, the correct answer is g/3.
Kafeel Ahmad khan said:
8 years ago
mg-T= ma ----> (1)
2T-mg=ma ----> (2).
Putting the value of T in equation (2).
2(mg-ma)-mg = ma,
2mg-2ma-mg = ma,
mg = 3ma,
a = g/3.
2T-mg=ma ----> (2).
Putting the value of T in equation (2).
2(mg-ma)-mg = ma,
2mg-2ma-mg = ma,
mg = 3ma,
a = g/3.
Purushottam said:
9 years ago
@Gurdeep @Gaurav.
Problem shows that;
m(g-a) = m(g+a)/2.
Problem shows that;
m(g-a) = m(g+a)/2.
ANup said:
9 years ago
While going up,
T1-mg=ma ------------- (1)
While going down,
Mg-t2=ma --------------- (2)
Solving 1 & 2,
2(mg-ma)-mg=ma.
Or, mg-2ma=ma.
Or, mg=3ma.
Or, a=g/3.
T1-mg=ma ------------- (1)
While going down,
Mg-t2=ma --------------- (2)
Solving 1 & 2,
2(mg-ma)-mg=ma.
Or, mg-2ma=ma.
Or, mg=3ma.
Or, a=g/3.
Daka said:
9 years ago
a = g/3.
The right answer is B.
The right answer is B.
Swap said:
9 years ago
The correct answer is g/3.
Joyer said:
9 years ago
The correct answer is +g/3.
@Vanraj and @Gurdeep, you have made a mistake in the condition of tension!
@Vanraj and @Gurdeep, you have made a mistake in the condition of tension!
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