Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 7 (Q.No. 2)
2.
The force applied on a body of mass 100 kg to produce an acceleration of 5 m/s2, is
Discussion:
7 comments Page 1 of 1.
Mayank Patel said:
4 years ago
Let,
Force = mass * acceleration.
F = m x a.
Here, m= 100kg, a=5m/s^2.
So substituting the values we get,
F=100 x 5.
F= 500 kgm/s^2 ~ 500N.
Force = mass * acceleration.
F = m x a.
Here, m= 100kg, a=5m/s^2.
So substituting the values we get,
F=100 x 5.
F= 500 kgm/s^2 ~ 500N.
Ibrahim azazmeh said:
6 years ago
F = m.a.
F =100 * 5,
F = 500N.
F =100 * 5,
F = 500N.
Prasanth said:
7 years ago
F = ma.
m = 100kg.
a = 5m/secsquare.
Calculation:
F=100 * 5.
F=500N.
m = 100kg.
a = 5m/secsquare.
Calculation:
F=100 * 5.
F=500N.
Satish kumar said:
8 years ago
Appy Newton Second law.
F =ma
m=100kg
a =5m/secsquare
calculation
F=100*5
F=500N.
F =ma
m=100kg
a =5m/secsquare
calculation
F=100*5
F=500N.
RAHUL said:
9 years ago
F = MA.
Where, M = 100 Kg, A = 5 m/s^2,
So, F = 100* 5 = 500 N.
Where, M = 100 Kg, A = 5 m/s^2,
So, F = 100* 5 = 500 N.
Joy said:
9 years ago
Unit of force is N which means kg.m/s2 if we do product of mass and acceleration force can be determined.
George said:
1 decade ago
Force = Mass*Acceleration
= 100*5
= 500n.
= 100*5
= 500n.
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