Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 13)
13.
A weight of 1000 N can be lifted by an effort of 80 N. If the velocity ratio is 20, the machine is
Discussion:
32 comments Page 1 of 4.
Shashidhar hiremath said:
2 years ago
Here, 1000N/80N = 12.5N
Then, Effcny = (12.5/V. R) * 100 = 62.5,
So, the eff. of a machine is 62.5% and 62.5% > 50%.
If the efficiency is greater than 50%, it is known as a "reversible machine".
Then, Effcny = (12.5/V. R) * 100 = 62.5,
So, the eff. of a machine is 62.5% and 62.5% > 50%.
If the efficiency is greater than 50%, it is known as a "reversible machine".
(4)
Akhilesha said:
4 years ago
I disagree with the answer. I think the answer is non-reversible because the maximum efficiency is 62.5 which greater than 50.
(2)
Raymond said:
4 years ago
What if the efficiency of a machine equals 50%, is it reversible or irreversible? Please explain.
DM Shihora said:
4 years ago
Thanks for the explanation.
Omid said:
6 years ago
@Aishu.
Because the efficiency is calculated in % age. So to bring it in percentage it's multiplied with 100.
Because the efficiency is calculated in % age. So to bring it in percentage it's multiplied with 100.
Akshat said:
6 years ago
What are the System of pulleys?
Subhash said:
6 years ago
It is Less than 50%.
(2)
Bhuvnesh Rana said:
7 years ago
No machine is an ideal machine in practice.
And the efficiency of a machine can never be 100% in practice.
And the efficiency of a machine can never be 100% in practice.
(1)
Aishu said:
7 years ago
Why should we multiply 100 with 20 in calculating velocity ratio? Please explain.
(1)
Jithin.k said:
7 years ago
What about the universal machine?
(1)
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