Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 6 (Q.No. 50)
50.
A lifting machine lifts a load of 1000N through a distance of 0.2 m by means of an effort of 200N through a distance of 1m. This machine is an ideal one.
Discussion:
4 comments Page 1 of 1.
Anand saroj said:
1 decade ago
w=1000N, P=200N, M.A=1000/200 = 5.
V.R= 1/0.2 = 5
Efficiency % = 5/5*100= 100 (idle).
V.R= 1/0.2 = 5
Efficiency % = 5/5*100= 100 (idle).
(1)
Gaurav said:
1 decade ago
Efficiency = Work output/Work input = 1000*0.2/500*0.1 = 100%.
So this is ideal case.
So this is ideal case.
Vinay BEL said:
5 years ago
w=1000N, P=200N, M.A=1000/200 = 5.
V.R= 1/0.2 = 5.
Efficiency % = 5/5*100= 100 (idle).
V.R= 1/0.2 = 5.
Efficiency % = 5/5*100= 100 (idle).
(2)
Vinod kr said:
1 decade ago
Efficiency = MA/VR.
= (1000/200)/(1/0.2)*100.
= 100%.
= (1000/200)/(1/0.2)*100.
= 100%.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers