Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 7)
7.
The minimum force required to slide a body of weight W on a rough horizontal plane is
Discussion:
49 comments Page 5 of 5.
Parth pandya said:
9 years ago
I think, Option A is right answer.
Parth said:
9 years ago
Right answer: W sin theta because in question already specified that minimum force. So whenever angel of inclination = angel of friction for rough horizontal plane then we have to put the answer W sin theta.
Rajesh khutdar said:
9 years ago
we know F = w R,
w = tan theta and for horizontal surface R = W
Therefore, Force required (F) = w tan theta
w = tan theta and for horizontal surface R = W
Therefore, Force required (F) = w tan theta
Ayyavu said:
10 years ago
W cos is answer. Force act in a horizontal.
Nadim said:
10 years ago
Answer is w sin theta because minimum force is required.
Saikumar said:
1 decade ago
Answer should be A as when force applied to slide a body at an angle theta.
Roni said:
1 decade ago
F equals to uR and u equals to tan of angle of friction. And R equals to W for horizontal plane. On this perspective, it should be the option (C).
Amit said:
1 decade ago
Weight w acts downward so that to move weight w we should only give force equals to frictional force. It will be wtanthita.
Andile said:
1 decade ago
How come because its a horizontal plane?
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