Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 7)
7.
The minimum force required to slide a body of weight W on a rough horizontal plane is
Discussion:
49 comments Page 1 of 5.
Akash said:
3 years ago
@All.
Actually, the question is not properly defined.
When a horizontal force is applied to the block the W tan (theta) is the right answer.
But when we apply a force that is inclined to the horizontal instead of a horizontal force then the minimum force is Wsin (θ).
Actually, the question is not properly defined.
When a horizontal force is applied to the block the W tan (theta) is the right answer.
But when we apply a force that is inclined to the horizontal instead of a horizontal force then the minimum force is Wsin (θ).
(5)
Dhananjay said:
4 years ago
If theta is the angle at which force is applied then the answer is A.
And If theta is friction angle and force is applied parallel to base then the answer is C.
And If theta is friction angle and force is applied parallel to base then the answer is C.
(1)
Vinit said:
8 years ago
According to me, the correct answer is A.
(1)
Yash said:
6 years ago
The answer should be wsinθ.
Anomi said:
7 years ago
Here it is a miskate in symbol, instead of θ it must be φ.
P=uR=tan φW.
P=uR=tan φW.
Muniraju B said:
7 years ago
The answer is wsinθ
W tanθ. Is for moving body upward on an inclined plane by neglecting the friction?
W tanθ. Is for moving body upward on an inclined plane by neglecting the friction?
Ayomidol said:
7 years ago
Answer is A. The horizontal component of the weight.
Chinku said:
7 years ago
Answer is w sinθ
Rajat said:
7 years ago
If we will apply a force at an angle equal to the angle of friction. Minimum force is required to slide that is equal to wsinθ. A is correct.
Ujjawal aggarwal said:
7 years ago
I agree with the given answer.
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