Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 7)

Engineering Mechanics

The minimum force required to slide a body of weight W on a rough horizontal plane is

W sin θ

W cos θ

W tan θ

none of these

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

49 comments Page 3 of 5.

Jayprakash said: 8 years ago

W sin θ is the right answer. Because of min force required.

Valak said: 8 years ago

Option A is correct.

LOKESH D said: 8 years ago

Option b is correct because in horizontal cos vertical sin and resultant is tan.

Deepak said: 8 years ago

If force is applied horizontally and 'θ' is the angle of friction, W tanθ is the right answer.

Samir said: 8 years ago

You are absolutely right. @Gaurav.

Rohit Koundal said: 7 years ago

Answer will be sinθ.

Anomi said: 7 years ago

Here it is a miskate in symbol, instead of θ it must be φ.

P=uR=tan φW.

Muniraju B said: 7 years ago

The answer is wsinθ

W tanθ. Is for moving body upward on an inclined plane by neglecting the friction?

Ayomidol said: 7 years ago

Answer is A. The horizontal component of the weight.

Rajat said: 7 years ago

If we will apply a force at an angle equal to the angle of friction. Minimum force is required to slide that is equal to wsinθ. A is correct.

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