Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 4 (Q.No. 10)
10.
The resultant of two forces P and Q (such that P > Q) acting along the same straight line, but in opposite direction, is given by
Discussion:
3 comments Page 1 of 1.
Sagar said:
7 years ago
Thnk you @Saikat.
Saikat das said:
8 years ago
if I take resultant R.
We can write
R =root(p2+q2+2pqcos x) ;here x= angle between p & q.
here , value of x=180°
then ,
R=root(p2+q2+2pqcos180°)
=root(p2+q2 -2pq),
=root(p-q)2,
=(p-q) --> Ans.
We can write
R =root(p2+q2+2pqcos x) ;here x= angle between p & q.
here , value of x=180°
then ,
R=root(p2+q2+2pqcos180°)
=root(p2+q2 -2pq),
=root(p-q)2,
=(p-q) --> Ans.
(2)
Arun said:
8 years ago
Anyone please describe it.
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