Mechanical Engineering - Compressors, Gas Dynamics and Gas Turbines - Discussion
Discussion Forum : Compressors, Gas Dynamics and Gas Turbines - Section 1 (Q.No. 1)
1.
In a four stage compressor, if the pressure at the first and third stage are 1 bar and 16 bar, then the delivery pressure at the fourth stage will be
Discussion:
32 comments Page 3 of 4.
Parseltounge said:
8 years ago
It follows a geometric pattern.
Narasimha said:
8 years ago
For multi satge compressor p2/p1=p3/p2=p4/p3,
p2/p1=p3/p2 from here we get p2=4 then by this relation p4/p3=p3/p2,
p4=64.
p2/p1=p3/p2 from here we get p2=4 then by this relation p4/p3=p3/p2,
p4=64.
Anj said:
8 years ago
Fourth stage means P5/P4 = 4*4*4*4 = 256.
Bipin said:
9 years ago
The answer can get by following this one P2/P1 = P3/P2 = P4/P3.
Rajeev raj singh said:
10 years ago
Since pressure ratio is constant for a compressor. So firstly found pressure ratio. And then make dual like p2/p1=p3/p2=p4/p3 and solve this.
Deepak kumar said:
1 decade ago
When we know that for multistage compressor p2/p1 = p3/p2 = p4/p3.
Since p3 = 16, p1 = 1 so p2/p1 = p3/p2 then p2 = 4 also p3/p2 = p4/p3.
16/4 = p4/16.
p4 = 64.
Since p3 = 16, p1 = 1 so p2/p1 = p3/p2 then p2 = 4 also p3/p2 = p4/p3.
16/4 = p4/16.
p4 = 64.
Francies said:
1 decade ago
We know that p2 = (p1p3)^(1/2).
Therefore p2 = (1*16)^(1/2),
p2 = 4 bar.
Therefore P4/p2=p3/p1,
P4 = 64 bar.
Therefore p2 = (1*16)^(1/2),
p2 = 4 bar.
Therefore P4/p2=p3/p1,
P4 = 64 bar.
Kanhai said:
1 decade ago
We know in multistage compressor:
P2/P1 = P3/P2 = P4/P3.
Since,
P3 = 16.
P1 = 1.
So from,
P2/P1 = P3/p2.
Hence,
P2 = 4.
Now P3/P2 = P4/P3.
P4 = 64.
P2/P1 = P3/P2 = P4/P3.
Since,
P3 = 16.
P1 = 1.
So from,
P2/P1 = P3/p2.
Hence,
P2 = 4.
Now P3/P2 = P4/P3.
P4 = 64.
Karthik said:
1 decade ago
How does it came 64?
Guna said:
1 decade ago
How to came 64?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers