### Discussion :: Compressors, Gas Dynamics and Gas Turbines - Section 1 (Q.No.1)

Hardik Patel said: (Jul 15, 2013) | |

In multistage compressor the pressure in each stage follows geometric progression: For 2nd stage: SQRT (1*16) = 4. For fourth stage: 4*4*4 = 64. |

Nanu Dayma said: (Nov 5, 2013) | |

Four stage compressor 3rd stage me intercooler hota so its temperature and pressure is constant 4 stage compressed so increased delivery pressure. |

Abhishek Chavan said: (Nov 20, 2013) | |

How to came 64 please explain the example? |

Guna said: (Feb 15, 2014) | |

How to came 64? |

Karthik said: (Mar 29, 2014) | |

How does it came 64? |

Kanhai said: (Apr 24, 2014) | |

We know in multistage compressor: P2/P1 = P3/P2 = P4/P3. Since, P3 = 16. P1 = 1. So from, P2/P1 = P3/p2. Hence, P2 = 4. Now P3/P2 = P4/P3. P4 = 64. |

Francies said: (Aug 7, 2014) | |

We know that p2 = (p1p3)^(1/2). Therefore p2 = (1*16)^(1/2), p2 = 4 bar. Therefore P4/p2=p3/p1, P4 = 64 bar. |

Deepak Kumar said: (Nov 11, 2014) | |

When we know that for multistage compressor p2/p1 = p3/p2 = p4/p3. Since p3 = 16, p1 = 1 so p2/p1 = p3/p2 then p2 = 4 also p3/p2 = p4/p3. 16/4 = p4/16. p4 = 64. |

Rajeev Raj Singh said: (Dec 2, 2015) | |

Since pressure ratio is constant for a compressor. So firstly found pressure ratio. And then make dual like p2/p1=p3/p2=p4/p3 and solve this. |

Bipin said: (Jun 20, 2016) | |

The answer can get by following this one P2/P1 = P3/P2 = P4/P3. |

Anj said: (Apr 25, 2017) | |

Fourth stage means P5/P4 = 4*4*4*4 = 256. |

Narasimha said: (Jul 22, 2017) | |

For multi satge compressor p2/p1=p3/p2=p4/p3, p2/p1=p3/p2 from here we get p2=4 then by this relation p4/p3=p3/p2, p4=64. |

Parseltounge said: (Aug 3, 2017) | |

It follows a geometric pattern. |

Mohit Kumar said: (Oct 23, 2017) | |

Good explanation @Natasha. |

Amit Ankush Vidarbh said: (Mar 22, 2018) | |

The delivery of forth stage=p5. p5=256. |

Pradeep said: (Nov 6, 2018) | |

And P5=256. |

Rahul said: (Jun 10, 2019) | |

Thanks all for explaining. |

Mayur Desai said: (Jul 7, 2019) | |

There is clearly mentioned about four stage it means; (P2/P1)*(P3*P2)*(P4*P3)*(P5*P4)= 4*4*4*4=256. So, the right answer is D. |

Rohit said: (Sep 23, 2019) | |

The delivery of forth stage = p5. p5 = 256. |

Suresh said: (Nov 16, 2019) | |

The first two values given are delivery pressures at 1st and 3rd stage compressors, we have to find delivery pressure at 4th compressor. We have p3/p2 = p4/p3 = p5/p4. p2 = 1, p4 = 16, p5 = ? => p3 = (1*16)^(1%2),=> p3 = 4. Similarly p4 = (p3*p5)^(1%2) => p5 = 64. |

Savan Kumar said: (Jan 4, 2020) | |

Thank you @Suresh. |

Vinod said: (Jan 11, 2020) | |

Why 256 bar is wrong? Explain. |

Sekhar said: (Feb 20, 2020) | |

The answer must be" D". Because delivery pressure at the fourth stage means we should find P5, not P4. So P5 = 4^4. |

Tarik said: (Apr 4, 2020) | |

D is the answer. |

Bawa said: (Apr 10, 2020) | |

Thanks @Suresh. |

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