Mechanical Engineering - Compressors, Gas Dynamics and Gas Turbines - Discussion
Discussion Forum : Compressors, Gas Dynamics and Gas Turbines - Section 1 (Q.No. 1)
1.
In a four stage compressor, if the pressure at the first and third stage are 1 bar and 16 bar, then the delivery pressure at the fourth stage will be
Discussion:
32 comments Page 2 of 4.
Anj said:
8 years ago
Fourth stage means P5/P4 = 4*4*4*4 = 256.
Narasimha said:
8 years ago
For multi satge compressor p2/p1=p3/p2=p4/p3,
p2/p1=p3/p2 from here we get p2=4 then by this relation p4/p3=p3/p2,
p4=64.
p2/p1=p3/p2 from here we get p2=4 then by this relation p4/p3=p3/p2,
p4=64.
Parseltounge said:
8 years ago
It follows a geometric pattern.
Mohit Kumar said:
8 years ago
Good explanation @Natasha.
Amit ankush vidarbh said:
7 years ago
The delivery of forth stage=p5.
p5=256.
p5=256.
Pradeep said:
7 years ago
And P5=256.
Rahul said:
6 years ago
Thanks all for explaining.
Mayur Desai said:
6 years ago
There is clearly mentioned about four stage it means;
(P2/P1)*(P3*P2)*(P4*P3)*(P5*P4)= 4*4*4*4=256.
So, the right answer is D.
(P2/P1)*(P3*P2)*(P4*P3)*(P5*P4)= 4*4*4*4=256.
So, the right answer is D.
Rohit said:
6 years ago
The delivery of forth stage = p5.
p5 = 256.
p5 = 256.
Suresh said:
6 years ago
The first two values given are delivery pressures at 1st and 3rd stage compressors, we have to find delivery pressure at 4th compressor.
We have p3/p2 = p4/p3 = p5/p4.
p2 = 1, p4 = 16, p5 = ?
=> p3 = (1*16)^(1%2),=> p3 = 4.
Similarly p4 = (p3*p5)^(1%2) => p5 = 64.
We have p3/p2 = p4/p3 = p5/p4.
p2 = 1, p4 = 16, p5 = ?
=> p3 = (1*16)^(1%2),=> p3 = 4.
Similarly p4 = (p3*p5)^(1%2) => p5 = 64.
(2)
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