Mechanical Engineering - Automobile Engineering - Discussion

Discussion Forum : Automobile Engineering - Section 3 (Q.No. 44)
44.
The gradient resistance to a vehicle having a mass of 980 kg moving on an incline of 10° is
1.6694 N
16.694 N
166.94 N
1669.4 N
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

Sám said:   4 years ago
@Vishwanath.

Weight, W = mass * gravity of earth.

Mahmood said:   4 years ago
@Vishwanath

9.81 is the gravity of Earth.

Vishwanath said:   4 years ago
9.81 is. ?

Radesh R said:   6 years ago
For 980*cos10 which resistance we need to prefer this formula?

Mohan kalki said:   7 years ago
Gradient resistance is given by Gr = W sin(angle of inclination).

So,
Gr = 980 * sin(10),
= 170.175 kg * 9.81,
=1669.41 N.

Sachin said:   1 decade ago
Gradient resistance Gr = W sin(angle).

980*9.81 sin10 = 1669.41N.

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