Logical Reasoning - Logical Problems - Discussion
Discussion Forum : Logical Problems - Type 4 (Q.No. 3)
Directions to Solve
The logic problems in this set present you with three true statements: Fact 1, Fact 2, and Fact 3. Then, you are given three more statements (labeled I, II, and III), and you must determine which of these, if any, is also a fact. One or two of the statements could be true; all of the statements could be true; or none of the statements could be true. Choose your answer based solely on the information given in the first three facts.
3.
| Fact 1: | All drink mixes are beverages. |
| Fact 2: | All beverages are drinkable. |
| Fact 3: | Some beverages are red. |
| I: | Some drink mixes are red. |
| II: | All beverages are drink mixes. |
| III: | All red drink mixes are drinkable. |
Discussion:
55 comments Page 2 of 6.
Rushit joshi said:
1 decade ago
All drinks mixes are beverages.
Some beverages are red.
Drink able red beverages = red drink mixes.
Some beverages are red.
Drink able red beverages = red drink mixes.
Ankit said:
1 decade ago
It is not necessary that all drinks are red. It can be understood clearly by making Venn diagrams.
Varshini said:
1 decade ago
What is the difference between drinkable and drinkmixes ?
Aditya said:
1 decade ago
Statement I and II seem to be correct . Why III is selected?
Dinesh said:
1 decade ago
Answer should be option (E) - None of the statements is a known fact.
Explanation :
First you draw 3 concyclic circles, innermost for drink mix, middle one for beverages and outer for drinkable. Then one more circle intersecting outer two circles(Drinkable and Beverages) but not innermost circle(Drink mix) as the statement 3 says only some beverages(need not drink mix) are red. So some beverages surely including some drinkable may not include drink mix.
Explanation :
First you draw 3 concyclic circles, innermost for drink mix, middle one for beverages and outer for drinkable. Then one more circle intersecting outer two circles(Drinkable and Beverages) but not innermost circle(Drink mix) as the statement 3 says only some beverages(need not drink mix) are red. So some beverages surely including some drinkable may not include drink mix.
Debasis said:
1 decade ago
Right, the option E should be the answer, else conclusion 1 and 3 are contradictory and there is no option for neither nor.
Jieling said:
1 decade ago
Statement III is right;.
Fact 1: All drink mixes = beverages;.
Fact 2: All beverages = drinkable.
According to this, all drink mixes = drinkable ===> regardless of the color. Therefore statement III (All red drink mixes are drinkable) is right.
Fact 1: All drink mixes = beverages;.
Fact 2: All beverages = drinkable.
According to this, all drink mixes = drinkable ===> regardless of the color. Therefore statement III (All red drink mixes are drinkable) is right.
Johnny said:
1 decade ago
The I and III statement should be the answer. Since all red drink mixes are drinkable so it could also fair to say that some drink mixes are red (and drinkable) which all refer all to beverages. I stand to be corrected>.
Jai said:
1 decade ago
Statement I and II seem to be correct . Why III is selected?
Susa said:
1 decade ago
"All drink mixes are beverages" but not all beverages are drink mixes so we can conclude "some beverages are drink mixes" and "Some beverages are red".
I. Some drink mixes are red. - Only in extreme case it is true.
II. All beverages are drink mixes - Is false as per above discussion.
"All drink mixes are beverages" and "All beverages are drinkable". So we can say "All drink mixes are drinkable".
III. All red drink mixes are drinkable - true as cumulative result.
So Option D) III Only is the correct answer.
I. Some drink mixes are red. - Only in extreme case it is true.
II. All beverages are drink mixes - Is false as per above discussion.
"All drink mixes are beverages" and "All beverages are drinkable". So we can say "All drink mixes are drinkable".
III. All red drink mixes are drinkable - true as cumulative result.
So Option D) III Only is the correct answer.
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