Discussion :: Logical Problems - Type 4 (Q.No.3)
The logic problems in this set present you with three true statements: Fact 1, Fact 2, and Fact 3. Then, you are given three more statements (labeled I, II, and III), and you must determine which of these, if any, is also a fact. One or two of the statements could be true; all of the statements could be true; or none of the statements could be true. Choose your answer based solely on the information given in the first three facts.
|Dasa Dilip said: (Dec 24, 2010)|
|Would you pls give me the demo ?|
|Pranav Mittal said: (Mar 23, 2011)|
|Its not necessary that some drink mixes are red. It might be the case that some drink mixes are red, but not necessarily. So, 1st statement is not true.
I will explain more: There are some beverages which are not drink mixes. So, it might be the case that all those beverages which are not drink mixes, are red. So, none of the drink mixes are red.
|Binod said: (Jul 26, 2011)|
|If all drink mixes are beverages then its not necessary that all beverages are drink mixes. So there may be some beverages which are not drink mixes and they may be red. so statement 1 is false. Correct me if I am wrong.|
|Prithvi said: (Jan 18, 2012)|
|Statement 1 is incorrect.
Drink mixes = orange juice,
Beverages have orange juice, grape juice, apple juice.
Now think and apply in current question.
|Prasant said: (Feb 29, 2012)|
|If (III) is correct, then (I) becomes correct automatically. Hence answer must be I & III.|
|Stephanie Odundo said: (Mar 10, 2012)|
|If (III) is correct then I also think I is correct because it gives us more information on the red drink mixes.|
|Virendra Singh said: (Mar 26, 2012)|
|1 draw circle as drink mixes come under beverage and beverage come under drinkable.As some beverages are red so this new circle come under drinkable touching beverages circle.now see
2according to first fact drink mixes may be red but not confirm.
3all beverage can't be drinkable it is reverse so it is wrong
4 all red drink mixes come under drinkable so it is true.
|Anand said: (Mar 29, 2012)|
As per your answer (drink mix = Orange juice, not only I but also statement no. III is also wrong. How can an Orange juice be in red color? Only grape can be in red. I accept I is wrong and also III.
|Karthik said: (Apr 7, 2012)|
|As all beverages are not drink mixes so the correct option is(d).|
|Shubham Goel said: (May 3, 2012)|
|First you draw 3 concyclic circles innermost for drink mix, middle one for beverages and outer for drinkable.
1.1st option is wrong because lets take two more small circles one intersect all circle, and other intersecting only beverages and drinkable so by this diagram its clear that there are two cases for 1st option so it can not be a answer.
2. Second option is clearly wrong.
3. Third option is true because when you draw a circle intersecting drink mix i.e. is inner one it is always come under drinkable.
And most important don't mix 1, 2, 3 statement take it separately and try to find answer by this method.
|Rushit Joshi said: (Jun 2, 2012)|
|All drinks mixes are beverages.
Some beverages are red.
Drink able red beverages = red drink mixes.
|Ankit said: (Jul 25, 2012)|
|It is not necessary that all drinks are red. It can be understood clearly by making Venn diagrams.|
|Varshini said: (Jul 28, 2012)|
|What is the difference between drinkable and drinkmixes ?|
|Aditya said: (Oct 30, 2012)|
|Statement I and II seem to be correct . Why III is selected?|
|Dinesh said: (Dec 11, 2012)|
|Answer should be option (E) - None of the statements is a known fact.
First you draw 3 concyclic circles, innermost for drink mix, middle one for beverages and outer for drinkable. Then one more circle intersecting outer two circles(Drinkable and Beverages) but not innermost circle(Drink mix) as the statement 3 says only some beverages(need not drink mix) are red. So some beverages surely including some drinkable may not include drink mix.
|Debasis said: (Jan 5, 2013)|
|Right, the option E should be the answer, else conclusion 1 and 3 are contradictory and there is no option for neither nor.|
|Jieling said: (Jan 12, 2013)|
|Statement III is right;.
Fact 1: All drink mixes = beverages;.
Fact 2: All beverages = drinkable.
According to this, all drink mixes = drinkable ===> regardless of the color. Therefore statement III (All red drink mixes are drinkable) is right.
|Johnny said: (Feb 13, 2013)|
|The I and III statement should be the answer. Since all red drink mixes are drinkable so it could also fair to say that some drink mixes are red (and drinkable) which all refer all to beverages. I stand to be corrected>.|
|Jai said: (Jun 21, 2013)|
|Statement I and II seem to be correct . Why III is selected?|
|Susa said: (Jul 18, 2013)|
|"All drink mixes are beverages" but not all beverages are drink mixes so we can conclude "some beverages are drink mixes" and "Some beverages are red".
I. Some drink mixes are red. - Only in extreme case it is true.
II. All beverages are drink mixes - Is false as per above discussion.
"All drink mixes are beverages" and "All beverages are drinkable". So we can say "All drink mixes are drinkable".
III. All red drink mixes are drinkable - true as cumulative result.
So Option D) III Only is the correct answer.
|Robot said: (Sep 19, 2013)|
|The 1st one is wrong because some beverages which are not drink mixes can be red. The second one is obvious.
Hence the third.
|Sudha said: (Dec 14, 2013)|
|Here it is given that in fact 1 "all drink mixes are beverages", it does not mean that all the beverages will only be drink mixes, there might be some beverages which are not drink mixes. Hence Statement II is false.
In Fact 3 it is given that "some beverages are red", it does not mean that those beverages would be only drink mixes, it may or may not be. Hence it is uncertain. So Statement I is false.
In Fact 2 it is given that "all beverages are drinkable", it means all drink mixes which were beverages and beverages which wee red and beverages themselves it means everything is drinkable. Hence Statement III is true which means all drink mixes which may be red are drinkable. Hence only Statement III is true. It would be easily understood when we use Venn diagrams.
|Nishtha said: (Mar 7, 2014)|
|It is given that all drinks are drinkable and some are red which can also be mixable so isn't the answer 1 only.|
|Danny said: (Apr 18, 2014)|
|Fact 1: All drink mixes are beverages : Here the mixes means for an eg we will take the mixes of fruit juice which is drinkable and called as beverages and could turn out to be any color.
Fact 2: All beverages are drinkable : So the mixes of juice are drinkable.
Fact 3: Some beverages are red : As we said it could turn out to be different color but some turn out to be red.
I: Some drink mixes are red : Yes agreed but it is uncertain.
II: All beverages are drink mixes : Not necessary.
III: All red drink mixes are drinkable : Yes it is drinkable thoe some may like some may not but it is drinkable.
Hope this may answer.
|Taba Tallum said: (May 31, 2014)|
|As per my opinion facts III is correct: As
Beverages are the subset of drinkable items.
Drink mixes are the subset of beverages.
Beverages may be red,orange, yellow, etc.
i.e. red beverages are the subset of beverages.
Statement 1: It may be true but not confirm because drink mixes are the subset of beverages and beverages may be red, orange, yellow, etc.
Statement 2: It is false because all drink mixes are beverages but all beverages may not be drink mixes.
Statement 3: It is true because all beverages are drinkable.
|Memory said: (Jul 5, 2014)|
|Option B also can because most of beverages are mixed with something which induces appetite.|
|Bjthe 1 said: (Aug 29, 2014)|
|All drink mixes are beverages. Then, all beverages must also be drink mixes. Why statement 2 is not correct?|
|Naveen Raj Goud said: (Sep 18, 2014)|
|Dear I will tell you the reason.
They said "all drink mixes" are "beverages"., it doesn't mean all "beverages" are "drink mixes".
That is the reason statement 2 is wrong.
Ex: "all probability questions" comes under "maths subject".
Does it mean "maths subject" has only "probability questions" not right. It is just a part in maths.
|James said: (Nov 12, 2014)|
|Just an interesting question.
"All red drink mixes are drinkable".
Here, you are accepting that red drink mixes are possible.
Doesn't that make "Some drink mixes are red" true?
|Jiten Dhimmar said: (Dec 3, 2014)|
|I can't understand need to more explanation.|
|Soumya said: (Dec 24, 2014)|
|1) All Drink mixes are --->Beverages.
2) Other drinks can also be --->Beverages.
3) All Beverages (1 and 2) are ---->Drinkable.
4) Some beverages are Red.
Coming to the Statements:
I: Some drink mixes are red. ------- Need not be, other drinks can be red.
II: All beverages are drink mixes. ---- Need not be, Beverages can include other drinks as well.
III: All red drink mixes are drinkable. ---- YES since all beverages (which include drink mixes) are drinkable.
|Ravi said: (Mar 5, 2015)|
|Every one here agrees that 3 is the right one. So lets not talk about it. The controversy here is about choice - one.
According to me,
If All Drink mixes are Beverages.
And Some beverages are red.
Possibility is - Yes some drink mixes can be red or may be not.
So since we are not sure if some drink mixes can be red, first choice can not be a fact (Actual Truth).
Even I got it wrong at the beginning then I understood.
|Tebas said: (Sep 18, 2015)|
|I can't understand.|
|Shaiva said: (Oct 12, 2015)|
|Let's say drink mixes are cola. Since, all colas are beverages and all beverages are drinkable. But some beverages are red. Apple juice is also beverage. All colas and apple juices are beverages, and all beverages are drinkable.
But no cola is an apple juice so 1 is wrong. Not all beverage are cola, since apple juice is also a beverage, so 2 is wrong. All red drink mixes (a red cola or mirinda) are drinkable, hence 3 is right. So D is right. Best way to do it by drawing venn diagram, you would get a better understanding.
|Shreya Agrawal said: (Oct 20, 2015)|
|It is specified that all drink mixes are beverages but it is not confirm that all the beverages are drink mixes. Hence only the 3rd statement is a fact.|
|Sagar said: (Nov 21, 2015)|
|Statement 1 is wrong because all drink mixes are beverages but all beverages are not drink mixes.
Beverages constitutes of drink mixes and non drink mixes. So coming to the statement 'some drink mixes are red' and we know SOME beverages are red.
These SOME may constitute of:
1. Complete drink mixes.
2. Complete non drink mixes.
3. Both drink mixes and non drink mixes.
So any of the combination is possible. So it may be true or may not be. That's why it is considered FALSE.
Hope you get it. Thank you.
|Guddu said: (Nov 27, 2015)|
|Use Venn diagrams.|
|Deepshikha said: (Dec 2, 2015)|
|Consider this example.
Drink mixes : Orange.
Beverages : Orange and Pomegranate.
All DM are B (so all orange are B).
All B are drinkable (so both orange and pomegranate are drinkable).
Some B are Red (so pomegranate are red).
1. Some DM are Red = No in my example (can't say in general).
2. All B are DM = No, It say all DM are B nor B are DM.
3. All red DM are drinkable = Yes.
|Enock said: (Jan 15, 2016)|
|(I) All drink mixes are beverages.
Thus, some beverages may or may not be drink mixes.
(II) all beverages are drinkable.
Thus some drinkable may not be beverages. It again means all drink mixes are drinkable since all beverages are drinkable.
(III) some beverages are red.
Thus, some may not be read. It again means that the beverages that are red may either be drink or non-drink mixes thus all may be drink mixes or all may be non-drink mixes or mixture of drink and non-drink mixes.
From the facts and analysis, we can say that all that part of beverages that are red can be drink mixes and if it is drink mixes then it is drinkable since all beverages are drinkable and all drink mixes are beverages. Therefore "All red drink mixes are drinkable" is a fact.
Moreover, since all red drink mixes is a fact, then "Some drink mixes is red" because if some were not red then how did they became drinkable in the fact we have already proven? Thus if some were not, then we wouldn't have all red drink mixes been drinkable.
Therefore option C is the answer.
|Srujana said: (Feb 4, 2016)|
|The name drink mixes indicates that it is drinkable. So, all red drink mixes are drinkable. All drink mixes are beverages. Some beverages (drink mixers) are red. Both I and III are correct.|
|Alex said: (Feb 9, 2016)|
|Let me clear the confusion for some:
"Choose your answer based solely on the information given in the FIRST THREE facts".
So just because the 3rd statement/question says "All red drink mixes are drinkable".
Doesn't make it a FACT from which you can base your decision.
|Kevin said: (May 20, 2016)|
|Drink mixes = beverages.
Beverages = drinkable.
Some beverages = red.
I) some drink mixes are red:
Ok, we know that all drink mixes are beverages but it is not explained that all beverages are drink mixes so this answer is not a known fact.
II) All beverages are drink mixes:
It is the same explanation than upper. We know that all drink mixes are beverages but it is not explained that all beverages are drink mixes so this answer is not a known fact.
III) All red drink mixes are drinkable:
For this one, we need to make the deduction. Indeed, we know that all drink mixes are beverages and that some beverages are red so some drink mixes are red and as all beverages = drink mixes = drinkable Finally all red drink mixes are drinkable which is a known fact.
|Hamza said: (Jul 3, 2016)|
|According to me, it should be C.|
|Mauleka Jain said: (Feb 7, 2017)|
|You are correct, I agree @Virendra.|
|Avi said: (Feb 17, 2018)|
|Answer should be C.|
|Peruth Nakimenya said: (Apr 11, 2019)|
|Statement I and II is the correct answer.|
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