Logical Reasoning - Letter and Symbol Series - Discussion
Discussion Forum : Letter and Symbol Series - Type 1 (Q.No. 6)
Directions to Solve
In these series, you will be looking at both the letter pattern and the number pattern. Fill the blank in the middle of the series or end of the series.
6.
ZA5, Y4B, XC6, W3D, _____
Answer: Option
Explanation:
There are three series to look for here. The first letters are alphabetical in reverse: Z, Y, X, W, V. The second letters are in alphabetical order, beginning with A. The number series is as follows: 5, 4, 6, 3, 7.
Discussion:
42 comments Page 3 of 5.
Akhilesh said:
8 years ago
If we divide the no. series in even and odd from 1 to further next so we can see at an odd place,
No. like 5,6 are at rightmost and in ascending order so next will be VE7.i.e. ZA5, XC6, VE7.
And at even place No.like 4,3 are in middle and in descending order so we can also generate next no;
that will be U2F. And the series will be Y4B, W3D, U2F.
No. like 5,6 are at rightmost and in ascending order so next will be VE7.i.e. ZA5, XC6, VE7.
And at even place No.like 4,3 are in middle and in descending order so we can also generate next no;
that will be U2F. And the series will be Y4B, W3D, U2F.
Manish Chauhsn said:
7 years ago
Thanks for the answer @Sundar.
Suresh said:
1 month ago
I am not understand the answer. Anyone, please help me to get this.
Rajesh said:
2 decades ago
I couldn't follow the number series explain please.
Kamlesh sen Damoh said:
1 decade ago
There are three series to look for here. The first letters are alphabetical in reverse: Z, Y, X, W, V. The second letters are in alphabetical order, beginning with A.
Second letter, fourth, sixth letter of 2series remain same. While 1, 3, 5, 7 letter of 1 series increase by one unit.
Second letter, fourth, sixth letter of 2series remain same. While 1, 3, 5, 7 letter of 1 series increase by one unit.
Vishal said:
2 decades ago
I think answer may be V2E (i.e)B.
Sundar said:
2 decades ago
Hi Rajesh and Vishal,
Pls look at this series ZA5, Y4B, XC6, W3D, ... carefully.
Here,
the number 5 is being RIGHT most place of the 1st set (ZA5).
the number 4 is being in the MIDDLE of the two letters (Y4B).
the number 6 is being RIGHT most place of the 2nd set
the number 3 is being in the MIDDLE of the two letters
..... and so on.
Now,
All the numbers placed at RIGHT most place are in Increasing order. 5, 6, ...
All the number placed in between the letters are in Decreasing order. 4, 3, ...
From the given series, clearly the next set will have a number in the RIGHT most place and it should be 7 (because 5, 6, 7,...).
ZYXW(?)---> V
ABCD(?)---> E
5 6 (?)---> 7
Therefore the answer is VE7.
Pls look at this series ZA5, Y4B, XC6, W3D, ... carefully.
Here,
the number 5 is being RIGHT most place of the 1st set (ZA5).
the number 4 is being in the MIDDLE of the two letters (Y4B).
the number 6 is being RIGHT most place of the 2nd set
the number 3 is being in the MIDDLE of the two letters
..... and so on.
Now,
All the numbers placed at RIGHT most place are in Increasing order. 5, 6, ...
All the number placed in between the letters are in Decreasing order. 4, 3, ...
From the given series, clearly the next set will have a number in the RIGHT most place and it should be 7 (because 5, 6, 7,...).
ZYXW(?)---> V
ABCD(?)---> E
5 6 (?)---> 7
Therefore the answer is VE7.
Nadhiya said:
2 decades ago
Answer will be b. Because number are in decreasing order.
Dhananjaya said:
2 decades ago
Here i got it
so the solution is
5-4,1
4+2,2
6-3,3
3+4,4
So we can see that in this series the first step is to add then to add the number in increasing order.
so the solution is
5-4,1
4+2,2
6-3,3
3+4,4
So we can see that in this series the first step is to add then to add the number in increasing order.
Shwetha said:
1 decade ago
But in the decreasing order 2 has to come after 3 instead of value 1 for v ans s actually v2e7 can anyone clear this doubt
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