Logical Reasoning - Letter and Symbol Series - Discussion
Discussion Forum : Letter and Symbol Series - Type 1 (Q.No. 2)
Directions to Solve
In these series, you will be looking at both the letter pattern and the number pattern. Fill the blank in the middle of the series or end of the series.
2.
B2CD, _____, BCD4, B5CD, BC6D
Answer: Option
Explanation:
Because the letters are the same, concentrate on the number series, which is a simple 2, 3, 4, 5, 6 series, and follows each letter in order.
Discussion:
44 comments Page 3 of 5.
Swap said:
1 decade ago
Because all numbers are moving in circular path.
First number 2 on B (i.e B2Cd) , then it get incremented by one i.e. 3 moves to next alphabet (i.e C) form BC3D (Ans). Then again number get incremented by one i.e 4 moves to next alphabet (i.e D) form BCD4, Now Here Alphabet are Three only (B, C, D) which are in circular form (means After D here B will come) , again numbers moves to 1st alphabet i.e 'B' Hence next incremented number get moved to B (i.e B5CD) by this way After BC6D number will come BCD7 (In Advanced).
First number 2 on B (i.e B2Cd) , then it get incremented by one i.e. 3 moves to next alphabet (i.e C) form BC3D (Ans). Then again number get incremented by one i.e 4 moves to next alphabet (i.e D) form BCD4, Now Here Alphabet are Three only (B, C, D) which are in circular form (means After D here B will come) , again numbers moves to 1st alphabet i.e 'B' Hence next incremented number get moved to B (i.e B5CD) by this way After BC6D number will come BCD7 (In Advanced).
Santhosh kumar p said:
1 decade ago
Very nice and I understanding this logic its good thanks.
Dee said:
1 decade ago
Thanks @Anusha.
Sunil brahmajosyula said:
1 decade ago
Base values are in the order of 4, ---, 6, 7, 8 find the base value of 5 from the options.
Surya teja.m said:
10 years ago
B2CD, _BC3D_, BCD4 = in B2CD B has number 2, in BCD4 D has a number 4 C has no number so answer is BC3D. The series of the number is 2, 3, 4.
B2 has 2 in first set of words, C has missing number so we have entered 3 for C in second set of words i.e., C3, D4 in third set of words.
B2 has 2 in first set of words, C has missing number so we have entered 3 for C in second set of words i.e., C3, D4 in third set of words.
Rubini said:
10 years ago
Hai friends I got the answer.
Harsha said:
9 years ago
I can't understand this logic.
Harsha said:
9 years ago
@Rubini tell me about the your answer.
WILLIAMKERY said:
9 years ago
First number B2CD = B + B + C + D = 4 "B2". First series start with 2.
Second number BC3D = B + C + C + C +D = 5 "C3". Second series Sequence 3.
Third Numbr BCD4 = B + C + D + D + D + D = 6 "D4" Third Series sequence 4.
Fourth Number B5CD = B + B + B + B + B + C + D =7 "B5" Alternator continue with number 5.
Fifth number BC6D =B +C + C + C + C + C + C + D =8 "C6" This the sequence with 6.
Second number BC3D = B + C + C + C +D = 5 "C3". Second series Sequence 3.
Third Numbr BCD4 = B + C + D + D + D + D = 6 "D4" Third Series sequence 4.
Fourth Number B5CD = B + B + B + B + B + C + D =7 "B5" Alternator continue with number 5.
Fifth number BC6D =B +C + C + C + C + C + C + D =8 "C6" This the sequence with 6.
(1)
GOMATHI said:
9 years ago
On this letter series the number will take b to c, and c to d, and again d to b like triangle wise. So first, b series they had been mentioned the substring of 2. So, what will happen, next to b, c series will get the next process, after that d, next c.
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