Logical Reasoning - Letter and Symbol Series - Discussion
Discussion Forum : Letter and Symbol Series - Type 1 (Q.No. 2)
Directions to Solve
In these series, you will be looking at both the letter pattern and the number pattern. Fill the blank in the middle of the series or end of the series.
2.
B2CD, _____, BCD4, B5CD, BC6D
Answer: Option
Explanation:
Because the letters are the same, concentrate on the number series, which is a simple 2, 3, 4, 5, 6 series, and follows each letter in order.
Discussion:
44 comments Page 2 of 5.
Anand upadhyay sagar said:
1 decade ago
watch anusha comments she is giving right answer
Deepak said:
1 decade ago
The letter are same for each case only no are change in every order for eg. first b2cd then one no increase it make bc3d
Murali said:
1 decade ago
Just keep concentrate on the numbers only. Which are given in series. Their is missing a number i.e '3', in the series 2, 3, 4, 5, 6. So the answer is 'B'.
Ritesh sinha said:
1 decade ago
Hi,
In the above quest they are asking for sequential series ok...just concentrate the series in first term b2cd = b+b+c+d(4 letter) in third term i.e bcd4 = b+c+d+d+d+d(total 6 letter)similarly 4th term contain 7 letter and last term contain 8 letter therefore according to series there must be contain 5 letter in 2nd term. now see the option i.e how many option u have that contain 5 letter only two option are there i.e option A & opt B so we go for option B only because no one term contain two word simultaneously more than one times except option B i.e in option A(it contain 5 letter but here two word i.e B,B and C,C simultaneously)thats y we go for option B. this is the right ans.
In the above quest they are asking for sequential series ok...just concentrate the series in first term b2cd = b+b+c+d(4 letter) in third term i.e bcd4 = b+c+d+d+d+d(total 6 letter)similarly 4th term contain 7 letter and last term contain 8 letter therefore according to series there must be contain 5 letter in 2nd term. now see the option i.e how many option u have that contain 5 letter only two option are there i.e option A & opt B so we go for option B only because no one term contain two word simultaneously more than one times except option B i.e in option A(it contain 5 letter but here two word i.e B,B and C,C simultaneously)thats y we go for option B. this is the right ans.
Sravanthi said:
1 decade ago
It is very simple thing letter is same its didn't change but number is in sequence the sequence is 2 3 4 5 6 and in the options b and d contains 3, but in d option it also had 2 so it is not correct option then b is the correct.
Narendra said:
1 decade ago
Tell me what is logic in this?
Megha Singhal said:
1 decade ago
In the above question they are asking for sequential series ok. Just concentrate the series in first term B2CD = B+B+C+D (4 letter) in third term i.e., BCD4 = B+C+D+D+D+D (total 6 letter) similarly 4th term contain 7 letter and last term contain 8 letter therefore according to series there must be contain 5 letter in 2nd term.
Now see the option i.e., how many option you have that contain 5 letter only two option are there i.e., option A & opt B so we go for option B only because no one term contain two word simultaneously more than one times except option B i.e., in option A (it contain 5 letter but here two word i.e., B, B and C, C simultaneously) thats why we go for option B. This is the right answer.
Now see the option i.e., how many option you have that contain 5 letter only two option are there i.e., option A & opt B so we go for option B only because no one term contain two word simultaneously more than one times except option B i.e., in option A (it contain 5 letter but here two word i.e., B, B and C, C simultaneously) thats why we go for option B. This is the right answer.
Chandana said:
1 decade ago
It is very simple see the question don't concentrate on letter please concentrate on numbers.
Sameera said:
1 decade ago
By looking at the numbers I got the answer its BC3D.
Dinesh said:
1 decade ago
Just see the base of 1st letter is 2, next time the base of second letter is 3, next time the base of 3rd letter is 4,
Similarly for next series... b2c3d4, b5c6d7,
Similarly for next series... b2c3d4, b5c6d7,
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