Logical Reasoning - Letter and Symbol Series - Discussion
Discussion Forum : Letter and Symbol Series - Type 1 (Q.No. 2)
Directions to Solve
In these series, you will be looking at both the letter pattern and the number pattern. Fill the blank in the middle of the series or end of the series.
2.
B2CD, _____, BCD4, B5CD, BC6D
Answer: Option
Explanation:
Because the letters are the same, concentrate on the number series, which is a simple 2, 3, 4, 5, 6 series, and follows each letter in order.
Discussion:
44 comments Page 3 of 5.
Sunil brahmajosyula said:
1 decade ago
Base values are in the order of 4, ---, 6, 7, 8 find the base value of 5 from the options.
Dee said:
1 decade ago
Thanks @Anusha.
Santhosh kumar p said:
1 decade ago
Very nice and I understanding this logic its good thanks.
Swap said:
1 decade ago
Because all numbers are moving in circular path.
First number 2 on B (i.e B2Cd) , then it get incremented by one i.e. 3 moves to next alphabet (i.e C) form BC3D (Ans). Then again number get incremented by one i.e 4 moves to next alphabet (i.e D) form BCD4, Now Here Alphabet are Three only (B, C, D) which are in circular form (means After D here B will come) , again numbers moves to 1st alphabet i.e 'B' Hence next incremented number get moved to B (i.e B5CD) by this way After BC6D number will come BCD7 (In Advanced).
First number 2 on B (i.e B2Cd) , then it get incremented by one i.e. 3 moves to next alphabet (i.e C) form BC3D (Ans). Then again number get incremented by one i.e 4 moves to next alphabet (i.e D) form BCD4, Now Here Alphabet are Three only (B, C, D) which are in circular form (means After D here B will come) , again numbers moves to 1st alphabet i.e 'B' Hence next incremented number get moved to B (i.e B5CD) by this way After BC6D number will come BCD7 (In Advanced).
Dinesh said:
1 decade ago
Just see the base of 1st letter is 2, next time the base of second letter is 3, next time the base of 3rd letter is 4,
Similarly for next series... b2c3d4, b5c6d7,
Similarly for next series... b2c3d4, b5c6d7,
Sameera said:
1 decade ago
By looking at the numbers I got the answer its BC3D.
Chandana said:
1 decade ago
It is very simple see the question don't concentrate on letter please concentrate on numbers.
Megha Singhal said:
1 decade ago
In the above question they are asking for sequential series ok. Just concentrate the series in first term B2CD = B+B+C+D (4 letter) in third term i.e., BCD4 = B+C+D+D+D+D (total 6 letter) similarly 4th term contain 7 letter and last term contain 8 letter therefore according to series there must be contain 5 letter in 2nd term.
Now see the option i.e., how many option you have that contain 5 letter only two option are there i.e., option A & opt B so we go for option B only because no one term contain two word simultaneously more than one times except option B i.e., in option A (it contain 5 letter but here two word i.e., B, B and C, C simultaneously) thats why we go for option B. This is the right answer.
Now see the option i.e., how many option you have that contain 5 letter only two option are there i.e., option A & opt B so we go for option B only because no one term contain two word simultaneously more than one times except option B i.e., in option A (it contain 5 letter but here two word i.e., B, B and C, C simultaneously) thats why we go for option B. This is the right answer.
Narendra said:
1 decade ago
Tell me what is logic in this?
Sravanthi said:
1 decade ago
It is very simple thing letter is same its didn't change but number is in sequence the sequence is 2 3 4 5 6 and in the options b and d contains 3, but in d option it also had 2 so it is not correct option then b is the correct.
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